Anthracene is a yellow, crystalline solid found in coal tar.Complete this structure for anthracene, C14H10, by adding bonds andhydrogen atoms as necessary.
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Anthracene is a yellow, crystalline solid found in coal tar. Complete this structure for anthracene, C14H10, by adding bonds and hydrogen atoms as necessary. If you would like to restore this structure to its original state, click on the drawing box, then click the button that looks like this: What type of hybrid orbitals are utilized by carbon in anthracene? How many sigma bonds and pi bonds are there in an anthracene molecu How many valence electrons occupy sigma-bond orbitals and how many
Draw the structure of anthracene and count the number sigma bonds, number of pi bonds, and number of valence electrons. Also identify the hybridization of carbon atoms present in anthracene.
Identify the hybridization of an atom by counting the number of sigma bonds.
If carbon is attached with 4 sigma bonds then the hybridization is sp3 ms mp^3sp3 .
If carbon is attached with 3 sigma bonds then the hybridization is sp2 ms mp^ m2sp2 .
If carbon is attached with 2 sigma bonds then the hybridization is sp mspsp .
The molecular formula of anthracene is C14H10 mC_ m14 mH_ m10C14H10 .
Calculatethedoublebondequivalenceasfollows:DBE=NC+1−((NH+NCl)−NN2)ThemolecularformulaforthegivencompoundisC14H10DBE=14+1−((10+0)−02)DBE=10So,thecompoundhas10doublebonds,itindicatesthepresenceofbenzeneringintheanthracene.eginarrayl\ mCalculate,, mthe,, mdouble,, mbond,, mequivalence,, mas,, mfollows:\\ mDBE, m = , mN_ mC, m + , m1, - left( frac m( mN_ mH, m + , mN_ mCl m) - mN_ mN m2 ight)\\ mThe, mmolecular, mformula, mfor, mthe, mgiven, mcompound, mis,, mC_14 mH_ m10\\ mDBE, m = ,14 m + 1, - left( frac m(10, m + , m0) - m0 m2 ight)\\ mDBE, m = ,,10\\ mSo,, mthe, mcompound, mhas,,10, mdouble, mbonds,, mit, mindicates, mthe, mpresence, mof, mbenzene, mring\\ min; mthe; manthracene.\endarrayCalculatethedoublebondequivalenceasfollows:DBE=NC+1−(2(NH+NCl)−NN)ThemolecularformulaforthegivencompoundisC14H10DBE=14+1−(2(10+0)−0)DBE=10So,thecompoundhas10doublebonds,itindicatesthepresenceofbenzeneringintheanthracene.
The structure of anthracene is,
Hybridization is sp2 ms mp^ m2sp2
Number of sigma bonds is 26.
Number of pi bonds is 7.
Number of valence electrons in sigma bonds is 52 electrons.
Number of valence electrons in pi bonds is 14 electrons.Ans:
sp2 ms mp^ m2sp2 hybrid orbitals are utilized by carbon in anthracene.
26 sigma bonds and 7 pi bonds are present in anthracene.
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The number of valence electrons in sigma bond are 52 and number of pi electrons are 14.