As you move from left to best in the period, we watch that the reactivity increases. ~ above the various other hand, as you move down a group in the nonmetals, the reactivity decreases. The farther right and also up you go on the periodic table, the greater theelectronegativity, leading to a more vigorous exchange the electrons.

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When cold weather is approaching, a lot of of vehicle drivers usually experience a warning light that indicates low-pressure on the dash board or they simply notification that the tires currently look a small less full than lock should have prior to the time.

The major reason for that low press indication is the drop in temperatures, which now reasons the waiting to gain denser and also in return, in turn lower the tires pressure.

In significance the tires will lose air pressure due to the fact that they contract in the cold season.

6 0
5 months ago

A item of carbon has a fixed of 13.5 g and also a volume of 15 ML
Karolina <17>



8 0
9 month ago

Please assist Assap!!!

A)distance = 0 and displacement = 0

B)distance = 10 meters and displacement = 0

D)distance = 10 meters and displacement = 10 meters

F)distance = 10 meters and displacement = 1 meter

In fact, displacement cannot be bigger than distance, due to the fact that distance is the complete distance took trip in any direction, if displacement takes into account the direction. When the thing moves just in one direction, distance and also displacement room equal; however, if the movement of the object consists of several motions into more directions (like going back and forth), the distance travelled is always larger than the displacement. For this reason, options C) and E) space wrong.


7 0
9 month ago
Given: NaCl + AgNO3 -> AgCl + NaNO3
vodomira <7>

The come your inquiry is 0.49 mole of AgCl



mass that AgNO₃ = 83 g

moles of AgCl = ?

mass of NaCl = excess

Balanced chemical reaction

NaCl + AgNO₃ ⇒ AgCl + NaNO₃


1.- calculate the molar fixed of AgNO₃

AgNO₃ = 108 + 14 + (16 x 3) = 170 g

2.- transform the grams the AgNO₃ to moles

170 g of AgNO₃ --------------- 1 mol

83 g of AgNO₃ -------------- x

x = (83 x 1) / 170

x = 0.49 moles

3.- calculate the moles of AgCl

1 mol that AgCl ------------ 1 mol that AgNO₃

x mol of AgCl ------------ 0.49 moles of AgNO₃

x = (0.49 x 1)/1

x = 0.49 moles of AgCl

6 0
9 month ago
Read 2 an ext urbanbreathnyc.coms
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