You are watching: Can the mean be negative
If the PDF the the variable is$$f(x)=\frac4\pi\fracx1+x^4\,
The average is therefore$$\frac4\pi\int_0^\infty\fracx^21+x^4\,\urbanbreathnyc.comrmdx=\sqrt2$$Yet the variance, for this reason the conventional deviation, is boundless since$$\frac4\pi\int_0^\infty\fracx(x-\sqrt2)^21+x^4\,\urbanbreathnyc.comrmdx$$diverges.
As with the distribution above, this indicates that the circulation is non-symmetric, a many the variance is added by the tail to the appropriate of the mean.
The sigma dominance only hold if the variable is generally distributed! In your case, the is probably since it all lies in the negative values? just imagine a high variance distribution and also then change to the left (take far a big value). Or it have the right to have fat tail. I suggest plot the data in some software program as a histogram, or density approximation and also it will be clear.
Thanks for contributing solution to urbanbreathnyc.comematics ridge Exchange!Please be sure to answer the question. Carry out details and share her research!
But avoid …Asking because that help, clarification, or responding to other answers.Making statements based upon opinion; back them increase with references or personal experience.
Use urbanbreathnyc.comJax to layout equations. Urbanbreathnyc.comJax reference.
See more: What Documentation Grants Express Authority To An Agent ? General Insurance Concepts Flashcards
To find out more, check out our tips on writing great answers.
article Your price Discard
Not the price you're looking for? Browse various other questions tagged statistics or questioning your very own question.
Why the typical deviation approximated through the range rule of ignorance much different from the typical deviation calculated straight from sample data?
site design / logo design © 2021 ridge Exchange Inc; user contributions licensed under cc by-sa. Rev2021.9.24.40305